Break equal-distance ties in the tree support MST by coordinates

This commit is contained in:
Hanif Koh
2026-09-08 01:49:57 +08:00
parent 60d1ceb580
commit e148865dd6
3 changed files with 73 additions and 1 deletions

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@@ -60,10 +60,15 @@ auto MinimumSpanningTree::prim(std::vector<Point> vertices) const -> AdjacencyGr
//This search is O(V) right now, which can be made down to O(log(V)). This reduces the overall time complexity from O(V*V) to O(V*log(E)).
//However that requires an implementation of a heap that supports the decreaseKey operation, which is not in the std library.
//TODO: Implement this?
// Break equal-distance ties on coordinates: the map is keyed by address, so its
// iteration order (and therefore the first minimum) would otherwise depend on where
// the vertices were allocated.
using MapValue = std::pair<const Point*, coordf_t>;
const auto closest = std::min_element(smallest_distance.begin(), smallest_distance.end(),
[](const MapValue& a, const MapValue& b) {
return a.second < b.second;
if (a.second != b.second)
return a.second < b.second;
return *a.first < *b.first;
});
//Add this point to the graph and remove it from the candidates.

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@@ -29,6 +29,7 @@ add_executable(${_TEST_NAME}_tests
test_polygon.cpp
test_mutable_polygon.cpp
test_mutable_priority_queue.cpp
test_minimum_spanning_tree.cpp
test_nozzle_volume_type.cpp
test_step.cpp
test_stl.cpp

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@@ -0,0 +1,66 @@
#include <catch2/catch_all.hpp>
#include <algorithm>
#include "libslic3r/MinimumSpanningTree.hpp"
#include "libslic3r/Point.hpp"
using namespace Slic3r;
// A 5x5 lattice: at every step of Prim's algorithm several candidates sit at the same
// distance from the tree, so the tie-break decides the tree's shape.
static std::vector<Point> lattice()
{
std::vector<Point> vertices;
for (int y = 0; y < 5; ++y)
for (int x = 0; x < 5; ++x)
vertices.emplace_back(Point::new_scale(x, y));
return vertices;
}
static std::vector<Point> sorted_neighbours(const MinimumSpanningTree &mst, const Point &vertex)
{
std::vector<Point> neighbours = mst.adjacent_nodes(vertex);
std::sort(neighbours.begin(), neighbours.end());
return neighbours;
}
TEST_CASE("Minimum spanning tree connects every vertex", "[MinimumSpanningTree]")
{
const std::vector<Point> vertices = lattice();
const MinimumSpanningTree mst(vertices);
REQUIRE(mst.vertices().size() == vertices.size());
size_t adjacency_entries = 0;
for (const Point &vertex : vertices) {
const std::vector<Point> neighbours = mst.adjacent_nodes(vertex);
REQUIRE(! neighbours.empty());
adjacency_entries += neighbours.size();
}
// A tree on n vertices has n - 1 edges, each listed from both ends.
REQUIRE(adjacency_entries == 2 * (vertices.size() - 1));
}
TEST_CASE("Minimum spanning tree does not depend on the order of the non-root vertices", "[MinimumSpanningTree][Regression]")
{
const std::vector<Point> vertices = lattice();
const MinimumSpanningTree reference(vertices);
// The root stays first: Prim's tree legitimately depends on where it starts.
// Every other order of the remaining vertices must give the same tree.
std::vector<std::vector<Point>> orders;
orders.emplace_back(vertices);
std::reverse(orders.back().begin() + 1, orders.back().end());
for (size_t shift = 1; shift + 1 < vertices.size(); ++shift) {
orders.emplace_back(vertices);
std::rotate(orders.back().begin() + 1, orders.back().begin() + 1 + shift, orders.back().end());
}
for (const std::vector<Point> &order : orders) {
const MinimumSpanningTree mst(order);
for (const Point &vertex : vertices) {
INFO("vertex " << vertex.x() << "," << vertex.y());
REQUIRE(sorted_neighbours(mst, vertex) == sorted_neighbours(reference, vertex));
}
}
}